Introduction Link to heading
Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1]
Output: 1
Example 2:
Input: [4,1,2,1,2]
Output: 4
Solution Link to heading
func singleNumber(nums []int) int {
xor := 0
for _, val := range nums {
xor ^= val
}
return xor
}